- Purpose of use
- 3^1000
- Comment/Request
- Good calc

[1] 2019/03/21 02:59 Male / Under 20 years old / Elementary school/ Junior high-school student / Very /

- Purpose of use
- Checking if e to the power of pi, minus pi, is as weird of a number as it first looks. Turns out it isn't.

[2] 2019/03/17 06:56 Male / Under 20 years old / High-school/ University/ Grad student / Very /

- Purpose of use
- Calculating astronomical distances and quantities.
- Comment/Request
- Would love to see greater than 102 digits possible without e.

[3] 2019/03/16 08:46 Male / 40 years old level / Self-employed people / Very /

- Purpose of use
- Checking that the concatenation of numbers from 1985 to 1995, in any order, is always divisible by 11 (1995 Argentina Math Olympiad problem)

[4] 2019/03/01 04:57 Male / 20 years old level / An office worker / A public employee / Very /

- Purpose of use
- Finding terms of sequence a(n)=sum over k={1...n} of |n^2-n!| mod 10
- Comment/Request
- Didn't work once I got to a(27). Apparently 112 [that was a(26)] + [|729-27!| mod 10] was too much for it to handle.

Request: a way to fix this issue - from Keisan
- Please set the digit >= 30.

[5] 2019/02/25 04:25 Male / Under 20 years old / High-school/ University/ Grad student / Useful /

- Purpose of use
- Locating terms of the sequence a(n) = the sum from k={1...n} of (|k^2-k!| mod 10).
- Comment/Request
- It worked very well. It was nice to find an advanced calculator to be able to actually not return zero for any value above 20.

[6] 2019/02/25 04:12 Male / Under 20 years old / High-school/ University/ Grad student / Very /

- Purpose of use
- saw if 7/33 was rational

[7] 2019/02/21 10:37 Male / Under 20 years old / Elementary school/ Junior high-school student / Useful /

- Purpose of use
- large numbers...

Thank you very much...

2^100000000 (8 zeros) = 2 ^ (10^8)

WONDERFUL! - Comment/Request
- Someday I look forward

to a more powerful calculator!

Right now, 2 ^ (10^8) seems plenty...

THANK YOU VERY MUCH!

Actually, I think I'd be interested in the square of

1 googolplex, which equals 10^(10^100) = 2 ^ (2^333.92) (approx.)

... the square of a googolplex would be = 2 ^ (2^334.92) (approx.) unless I'm wrong

because if you double the exponent (((the first exponent)))

you square the "actual value" (unless I'm wrong)

So, to square a googolplex,

simply add one (1) to the SECOND exponent

(please see the above equation)

Since the SECOND exponent is

"on two"

that is equivalent to doubling the FIRST exponent

which is equivalent to squaring a googolplex

(10^(10^100)) = googolplex

((10^(10^100))^2 = the square of a googolplex = 2^(2^334.92) (approx.)

(unless I'm wrong)

It would be nice if we had a calculator that could quickly verify that!

With love and respect,

[8] 2019/02/20 03:42 Male / 60 years old level or over / Others / Very /

- Purpose of use
- Ham radio

[9] 2019/02/17 14:58 Male / 50 years old level / Others / Very /

- Purpose of use
- counting how many pills I have to take before death
- Comment/Request
- not enough digits

[10] 2019/02/17 02:54 Male / 60 years old level or over / Elementary school/ Junior high-school student / Very /

**The hyperlink to [Calculator]**