# Jacobi amplitude function am(u,k) (chart) Calculator

## Calculates a table of the Jacobi amplitude function am(u,k) and draws the chart.

 k -1≦k≦1 [ initial value u increment repetition ]
 $\normal Jacobi\ amplitude\ am(u,k)\\[10](1)\ am(u,k)=\phi=F^{-1}(u,k),\hspace{20} |am(u,k)|\le \pi\\\hspace{25}u=F(\phi,k)={\large\int_{\small 0}^{\hspace{25}\phi}\frac{d\theta}{\sqrt{1-k^2sin^2\theta}}}\\[10](2)\ sn(u,k)=sin(am(u,k))=sin\phi\\\hspace{25}cn(u,k)=cos(am(u,k))=cos\phi\\\hspace{25}dn(u,k)=\frac{\partial am(u,k)}{\partial u} \\$
Jacobi amplitude function am(u,k) (chart)
 [1-2] /2 Disp-Num5103050100200
[1]  2012/08/13 12:53   Female / 20 years old level / High-school/ University/ Grad student / Very /
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PhD investigation
[2]  2009/08/03 21:48   Male / Under 20 / A high school student / Very /
Purpose of use
Regular features of interest functions.I found them to solve equations in wolframalpha.com
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