# Bisection method Calculator

## Calculates the root of the given equation f(x)=0 using Bisection method. | |||

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- Comment/Request
- how do i input log of base 10?

[1] 2019/04/26 02:36 Female / 20 years old level / High-school/ University/ Grad student / Useful /

- Purpose of use
- assignment
- Bug report
- not working for trignometric

[2] 2019/02/21 23:51 Male / 20 years old level / High-school/ University/ Grad student / Useful /

- Bug report
- i put 2xcos2x +(x+1)^2=0 solve by bisection method [-3,-2] it is not taking
- from Keisan
- Please input the formula as below.

2*x*cos(2*x)+(x+1)^2

[3] 2018/12/02 03:25 Male / 50 years old level / High-school/ University/ Grad student / Useful /

- Purpose of use
- teaching
- Comment/Request
- very useful I have one question how to solve 2xcos2x + (x+1)^2=0 by bisection method

[4] 2018/12/02 03:19 Male / 50 years old level / A teacher / A researcher / Very /

- Comment/Request
- i have put a function √x-cosx and value of a and b (0,1) but still iam unable to get the solution
- from Keisan
- Please input

"sqrt(x)-cos(x)" in

f(x).

[5] 2018/10/29 21:55 Male / 20 years old level / High-school/ University/ Grad student / Not at All /

- Purpose of use
- Studying

[6] 2018/10/06 05:59 Female / Under 20 years old / High-school/ University/ Grad student / Useful /

- Purpose of use
- Double checking work against multiple online calculators.
- Comment/Request
- :)

[7] 2018/04/27 13:00 Male / 20 years old level / High-school/ University/ Grad student / A little /

- Purpose of use
- Assignment

[8] 2018/03/25 20:55 Male / Under 20 years old / High-school/ University/ Grad student / Very /

- Purpose of use
- To check my homework
- Comment/Request
- how to designate the superscript like as if we have 3.61111×10−8T 3 − 6.95238×10−5T 2 + 0.0805437T − 0.3 =0 if we have such kind of questions in Bisection method

[9] 2018/03/21 22:37 Male / 20 years old level / High-school/ University/ Grad student / Very /

- Purpose of use
- checking answer for my assingments

[10] 2018/03/18 18:03 Male / 20 years old level / High-school/ University/ Grad student / Very /

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