LU Decomposition Calculator

Decomposing a square matrix into a lower triangular matrix and an upper triangular matrix. Partial pivot with row exchange is selected.


    1. (enter a data after click each cell in matrix)
Matrix A 
{aij}   

LU Decomposition
The row pivot information in LU decomposition is in one-dimensional array P.

LU Decomposition
[1-10] /12Disp-Num
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[1]  2019/03/06 08:46   Male / 20 years old level / High-school/ University/ Grad student / Very /
Purpose of use
Check my own code
[2]  2019/03/01 04:30   Male / 20 years old level / High-school/ University/ Grad student / Very /
Purpose of use
Testing my own algorithm
[3]  2019/02/15 12:53   Male / Under 20 years old / High-school/ University/ Grad student / A little /
Purpose of use
checking work
[4]  2019/02/15 04:13   Male / 20 years old level / High-school/ University/ Grad student / A little /
Comment/Request
I need it to work with a 3x4 matrix
[5]  2019/02/12 19:03   Male / 20 years old level / High-school/ University/ Grad student / Very /
Purpose of use
quick validation
[6]  2019/02/08 03:41   Female / 20 years old level / High-school/ University/ Grad student / Useful /
Purpose of use
university coursework checking
[7]  2018/12/09 05:16   Male / Under 20 years old / High-school/ University/ Grad student / Useful /
Purpose of use
Check handwritten work.
[8]  2018/11/14 22:43   Male / 20 years old level / High-school/ University/ Grad student / Very /
Purpose of use
Ensure my hand-written decomposition process was done correctly.
[9]  2018/10/21 03:01   Male / 40 years old level / Self-employed people / Not at All /
Purpose of use
Just wanted to check to see if my results matched what the calculator said.
Comment/Request
Your calculator is wrong. I entered a matrix like this:

[1 2 3]
[4 5 6]
[7 8 9]. And it said that the LU decomposition was this:

L [1 0 0] U=....
[0.14 1 0]
[0.57 0 1]

That by itself is wrong, the correct answer is:

L=[1 0 0] U=..... You should figure out to see what's wrong with your algorithm.
[4 1 0]
[7 2 1]
from Keisan
The result seems to be correct.

L
[1 0 0]
[0.14.. 1 0]
[0.57.. 0.5 1]

U
[7 8 9]
[0 0.85.. 1.71..]
[0 0 5.E-15]

LU =
[7 8 9]
[1 2 3]
[4 5 6]

(Partial pivot with row exchange P_i = [3 1 2])
[10]  2018/10/11 15:57   Female / 20 years old level / High-school/ University/ Grad student / Very /
Purpose of use
helping with my exam

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